Differentiation of $ \cos v$

Let $ y = \cos v$. By item 29, §1.1, this may be written

$\displaystyle y = \sin \left ( \frac{\pi}{2} - v \right ).
$

Differentiating by formula (XI),

\begin{displaymath}
\begin{array}{ll}
\frac{dy}{dx}
& = \cos \left ( \frac{\pi...
...frac{dv}{dx} \right )\\
& = -\sin x \frac{dv}{dx}.
\end{array}\end{displaymath}

(Since $ \cos \left ( \frac{\pi}{2} \right ) = \sin v$, by 29, §1.1.) Therefore,

$\displaystyle \frac{d}{dx} (\cos v) = -\sin v \frac{dv}{dx},
$

(equation (XII) in §5.1 above).



david joyner 2008-08-11