Differentiation of $ {\rm arccot}u$

Let $ y = {\rm arccot}\ v$; then $ y = \cot\ y$. This function is defined for all values of $ v$, and is many-valued.In order to make it single-valued, only values of $ y$ between 0 and $ \pi$ are considered; that is, the smallest positive arc whose cotangent is $ v$.

Following the method of the last section, we get

$\displaystyle \frac{d}{dx}({\rm arccot}\, v) = -\frac{\frac{dv}{dx}}{1 + v^2}
$

(equation (XXI) in §5.1 above).



david joyner 2008-08-11