Differentiation of $ {\rm arccsc}\, v$

Let

$\displaystyle y =\ {\rm arccsc}\, v;
$

then

$\displaystyle v =\ \csc\, y.
$

This function is defined for all values of $ v$ except those lying between $ -1$ and $ +1$, and is seen to be many-valued. To make the function single-valued, $ y$ is taken as the arc of smallest numerical value whose cosecant is $ v$. This means that if $ v$ is positive, we confine ourselves to points on the arc $ AB$ (Figure 5.11), $ y$ taking on values between 0 and $ \frac{\pi}{2}$ ( $ \frac{\pi}{2}$ may be included); and if $ v$ is negative, we confine ourselves to points on the arc $ CD$, $ y$ taking on values between $ -\pi$ and $ -\frac{\pi}{2}$ ( $ -\frac{\pi}{2}$ may be included).

Figure 5.11: The inverse secant function $ {\rm arccsc}\x$ using SAGE.
\includegraphics[height=6cm,width=7cm]{arccsc2.eps}

Figure 5.12: The standard branch of $ {\rm arccsc}\x$ using SAGE.
\includegraphics[height=5cm,width=8cm]{arccsc3.eps}

Differentiating with respect to $ y$ by XVI and following the method of the last section, we get

$\displaystyle \frac{d}{dx}({\rm arccsc}v) = -\frac{\frac{dv}{dx}}{v\sqrt{v^2 - 1}}
$

(equation (XXIII) in §5.1 above).

david joyner 2008-08-11